## what is the speed of the block at the bottom of the ramp c) at its maximum value at the locations where the skater turns and goes back in the opposite direction.

The block remains at rest if μs> tan

adown Δx = 0 + 2*2*0.8.

d) It will take less time to return to the point from which it was released.

If it falls, what becomes of this energy just before it hits the ground?

We are going to find the minimum speed you require to complete the loop, we’ll do this via an energy argument. Which requires more work: lifting a 50-kg sack a vertical distance of 2 m or lifting a 25-kg sack a vertical distance of 4 m? Read about our approach to external linking. You have a block of ice on a ramp with an angle of 23 degrees when it slips away from you. When the useful energy output of a simple machine is 100 J, and the total energy input is 200 J, the efficiency is _______. What force is responsible for the decrease in the mechanical energy of the block?

v2final = vo2 + 2 As the block slides across the floor, what happens to its kinetic energy K, potential energy U, and total mechanical energy E? b) equal to the amount of potential energy loss in going from the initial location to the bottom. When he releases the ball from chin height without giving it a push, how will the ball's behavior differ from its behavior on Earth? d) Immediately before hitting the ground the apple's energy is kinetic energy; when it hits the ground, its energy becomes thermal energy. Following are answers to the practice questions: 40 m/s. Sign in, choose your GCSE subjects and see content that's tailored for you. The coefficients of friction for A block starts from the bottom of a ramp of length 4 m and height 3 m with an initial velocity up the ramp of 4 m/s. tdown= 0.89 s. (d) Final speed: Use Going up: These are your final results. The block slows as it slides up the ramp and eventually stops. Record the time it takes for the trolley to travel the last 30 cm of the ramp in a table like the one shown below. Next, record the time it takes for the trolley to travel the final section of the ramp. Practise recording the time it takes for the trolley to travel the length of the ramp. Remember that these are practise results. Will the Intuitive explanation:  Following are answers to the practice questions: 220 N Ignore friction and air resistance. Suggested practical - investigating acceleration down a ramp, Investigate the acceleration of a trolley down a ramp, make and record measurements of length and time accurately, use appropriate apparatus and methods to measure motion.    0.8 = tdown2.

Although the simulation doesn't give the skater's speed, you can calculate it because the skater's kinetic energy is known at any location on the track. the block on the ramp are: μs = 0.6 and μk = 0.5. When the skater starts 7 m above the ground, how does the speed of the skater at the bottom of the track compare to the speed of the skater at the bottom when the skater starts 4 m above the ground? Avoid making the ramp too steep, as this will cause the trolley to roll too quickly, which could make measuring difficult.   vfinal= 1.8 m/s. slope. To do this, release the trolley from the top of the ramp again but this time start the stop clock when the trolley reaches the last 30 cm of the ramp. The coefficients of friction for the block on the ramp are: μ s = 0.6 and μ k = 0.5.. Calculate the acceleration of the trolley when descending the entire length of the ramp using acceleration (m/s. ) Remember to first convert 30 cm into metres by dividing it by 100 (there are 100 cm in 1 m). Remember that the change in speed is from 0 m/s to the calculated result. Calculate the speed of the trolley when it was descending the last 30 cm of the ramp using the equation: speed (m/s) = distance (m) ÷ time (s). One common application of conservation of energy in mechanics is to determine the speed of an object. A cart starts at the top of a 50-m slope at an angle 38 degrees. Rank speed from greatest to least at each point. μk N = - (0.6+0.4) mg = -mg.     aup = -g, (a) Distance traveled.

Now observe the potential energy bar on the Bar Graph. Distance-time and velocity-time graphs can be a useful way of analysing motion. (Hint:  Find tan θ.). An apple hanging from a limb has potential energy because of its height. If the coefficient of static friction is a low 0.050, how much force will you need to apply to overcome the weight pulling the block down the ramp and static friction? Now compare the times for sliding up and sliding down: Use a coordinate system in which the x-direction is aligned up the ramp b) the same at all locations of the track. Where on the track is the skater's kinetic energy the greatest? This is the principle of conservation of energy and can be expressed as E1=E2. What would happen if the angle of the ramp was different? In this practical activity, it is important to: To investigate the acceleration of an object on an angled ramp. Since μs= 0.6, the block backslides. down: friction and gravity work in the opposite direction; the block Acceleration depends on speed and time. When it hits the ground? Set up a ramp balanced on a wooden block at one end. (Note that the ramp is a 3-4-5 triangle, so sin θ = 0.6 and time.

Sliding up takes more time than sliding down. Mark out 30 cm at the end of the ramp. time than sliding down. Calculate the speed of the trolley when it was descending the last 30 cm of the ramp using the equation: speed (m/s) = distance (m) ÷ time (s). The block slows as it slides up the ramp and eventually stops.

If the skater started from rest 4 m above the ground (instead of 7m), what would be the kinetic energy at the bottom of the ramp (which is still 1 m above the ground)?

Use the result from above as the final speed and take the initial speed of the trolley as 0 m/s. Our team of exam survivors will get you started and keep you going. Using conservation of energy, find the speed vb of the block at the bottom of the ramp. c) K decreases;U stays the same;E decreases.

block remain at rest or will it slide down the ramp again? (c) Sliding time down: Use Use:  accelerates slowly. vb = (v2)+2gh) As the block slides across the floor, what happens to its kinetic energy K, potential energy U, and total mechanical energy E? Use:

Since the energy is conserved, the change in the kinetic energy is equal to the negative of the change in the potential energy: K2−K1=−(U2−U1), or ΔK1=−ΔU2. For ease, we’ll ignore friction! (Select all that apply.). To do this, release the trolley from the top of the ramp, start the stop clock and record the time taken for the trolley to move the whole distance of the ramp.

b) the object's final speed was the same as its initial speed. Express your answer in terms of some or all the variables m, v, and h and any appropriate constants. The force along the ramp is Going cos θ = 0.8). adown = (0.6-0.4) g = 0.2 g = 2.0 m/s2. Find the amount of energy E dissipated by friction by the time the block stops. There are different ways to investigate the acceleration of an object down a ramp. Repeat this twice more, and record a mean time for the trolley to travel the last 30 cm of the ramp.

First we need to find the minimum speed required at the top of the loop. x-direction:     maup = -mg sin θ - Sliding up takes less an initial velocity up the ramp of 4 m/s. c) at its maximum value at the lowest point of the track. Speed and velocity refer to the motion of an object.

The amount of kinetic energy an object has depends on its mass and its speed.

1) Total Energy at Initial Position= 5145 J.

To get the minimum required speed to make the loop the loop, at the top of the loop we require the normal force (\(N\)) to be 0. What is its speed at the bottom of the 6.0 m ramp? = change in speed (m/s) ÷ time taken (s). adownt2down    or Fossil fuels, hydroelectric power, and wind power ultimately get their energy from _______. v = vo + auptup, x-direction:     mg sin θ - μk N = madown   What is the cart’s speed at the bottom? time and record this also. Based on the previous question, which statement is true? Sliding up takes less Remember that the change in speed is from 0 m/s to the calculated result. Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g=30 m/s2. Calculate the acceleration of the trolley when descending the entire length of the ramp using acceleration (m/s2) = change in speed (m/s) ÷ time taken (s). friction and gravity work together; the block decelerates quickly. In the current window, click and drag a new track (the shape with three circles in the bottom left of the window), and place it near the upper left end of the existing track until the two connect. What will the kinetic energy of a pile driver ram be if it starts from rest and undergoes a 10 kJ decrease in potential energy? Using conservation of energy, find the speed vb of the block at the bottom of the ramp. Using conservation of energy, find the speed vb of the block at the bottom of the ramp. Block on a Ramp. This means that the kinetic plus potential energy at one location, say E1=K1+U1, must be equal to the kinetic plus potential energy at a different location, say E2=K2+U2. Ignoring friction, the total energy of the skater is conserved. We can be certain that ____. Scalar and vector quantities - OCR Gateway, Mass, weight and gravitational field strength - OCR Gateway, Home Economics: Food and Nutrition (CCEA). Then, click and drag on the circles to stretch and/or bend the track to make it look as shown below. θ= 3/4. It is important to record results in a suitable table, like the one below: Use the result from above as the final speed and take the initial speed of the trolley as 0 m/s.